5*x^2-16*x+11=0

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Solution for 5*x^2-16*x+11=0 equation:



5x^2-16x+11=0
a = 5; b = -16; c = +11;
Δ = b2-4ac
Δ = -162-4·5·11
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-6}{2*5}=\frac{10}{10} =1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+6}{2*5}=\frac{22}{10} =2+1/5 $

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